Study guide
3.1 Integer Exponents & Laws of Exponents
ACCUPLACER Quantitative Reasoning, Algebra, and Statistics Exam
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1 Chapter 1: Rational Numbers & Operations
1.1 Rational Number Arithmetic & Signed Numbers 1.2 Fractions, Decimals, & Mixed Numbers Operations 1.3 Absolute Value, Number Line, & Estimation
2 Chapter 2: Ratios, Proportions & Rates
2.1 Ratios, Unit Rates, & Dimensional Analysis 2.2 Proportions & Direct/Inverse Variation 2.3 Percent Applications, Markup, Discount, & Simple Interest
3 Chapter 3: Exponents & Scientific Notation
3.1 Integer Exponents & Laws of Exponents 3.2 Scientific Notation & Operations
4 Chapter 4: Algebraic Expressions
4.1 Evaluating & Translating Algebraic Expressions 4.2 Simplifying, Combining Like Terms, & Factoring
5 Chapter 5: Linear Equations & Inequalities
5.1 Solving Single-Variable Linear Equations 5.2 Solving & Graphing Linear Inequalities 5.3 Systems of Linear Equations
6 Chapter 6: Linear Applications & Graphing
6.1 Slope & Rate of Change 6.2 Forms of Linear Equations & Graphing 6.3 Linear Modeling & Inequality Graphs
7 Chapter 7: Probability & Set Theory
7.1 Fundamental Probability Concepts 7.2 Set Theory, Operations, & Venn Diagrams
8 Chapter 8: Descriptive Statistics & Data Displays
8.1 Measures of Center: Mean, Median, Mode, & Weighted Average 8.2 Measures of Spread: Range, IQR, Variance, & Standard Deviation 8.3 Data Displays: Histograms, Box Plots, & Scatter Plots
9 Chapter 9: Geometry Concepts & Measurement
9.1 2D Geometry: Perimeter, Area, & Circles 9.2 3D Geometry: Surface Area & Volume of Solids 9.3 Triangles, Angles, & the Pythagorean Theorem
3.1 Integer Exponents & Laws of Exponents
Key Takeaways Explain This Topic AI
An exponent denotes repeated multiplication of a base: a^n = a · a · ... · a (n factors), where a is the base and n is the power.
The core exponent rules simplify expressions: Product Rule (a^m · a^n = a^(m+n)), Quotient Rule (a^m / a^n = a^(m-n)), and Power of a Power ((a^m)^n = a^(mn)).
The Zero Exponent Rule states that a^0 = 1 for all non-zero bases (a ≠ 0), while 0^0 is mathematically undefined.
Negative exponents represent multiplicative inverses (reciprocals): a^(-n) = 1 / a^n and (a/b)^(-n) = (b/a)^n for non-zero a and b.
Exponents apply strictly to their immediate base: -x^n = -(x^n) ≠ (-x)^n, and exponents never distribute across addition or subtraction: (x + y)^n ≠ x^n + y^n.
Last updated: August 2026
Fundamentals of Exponential Notation
Exponential notation provides a compact mathematical framework for expressing repeated multiplication of a number or algebraic expression by itself. On the ACCUPLACER Quantitative Reasoning, Algebra, and Statistics (QAS) test, mastery of integer exponents and their operational laws is foundational for simplifying algebraic expressions, solving polynomial equations, and manipulating formulas across quantitative disciplines.
- Anatomical Definition of an Exponential Expression
- An exponential term consists of two primary components: a n a^n a n
Base ( a a a ) : The repeated factor or quantity being multiplied.
Exponent ( n n n ) : Also referred to as the power or index , the exponent indicates the exact number of times the base appears as a multiplying factor.
For any real number a a a and any positive integer n n n : a n = a ⋅ a ⋅ a ⋅ ⋯ ⋅ a ⏟ n factors of a a^n = \underbrace{a \cdot a \cdot a \cdot \dots \cdot a}_{n \text{ factors of } a} a n = n factors of a a ⋅ a ⋅ a ⋅ ⋯ ⋅ a
Examples :
3 4 = 3 ⋅ 3 ⋅ 3 ⋅ 3 = 81 3^4 = 3 \cdot 3 \cdot 3 \cdot 3 = 81 3 4 = 3 ⋅ 3 ⋅ 3 ⋅ 3 = 81
( − 2 ) 5 = ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) = − 32 (-2)^5 = (-2) \cdot (-2) \cdot (-2) \cdot (-2) \cdot (-2) = -32 ( − 2 ) 5 = ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) = − 32
- x 3 = x ⋅ x ⋅ x x^3 = x \cdot x \cdot x x 3 = x ⋅ x ⋅ x
- The Critical Sign and Parentheses Distinction
One of the most frequent traps on the ACCUPLACER exam involves distinguishing between expressions with and without grouping parentheses around negative bases. The exponent operates strictly on the immediate symbol or grouped quantity to its left.
Expression Base Expanded Form Evaluated Result
( − 3 ) 4 (-3)^4 ( − 3 ) 4 − 3 -3 − 3 ( − 3 ) ⋅ ( − 3 ) ⋅ ( − 3 ) ⋅ ( − 3 ) (-3) \cdot (-3) \cdot (-3) \cdot (-3) ( − 3 ) ⋅ ( − 3 ) ⋅ ( − 3 ) ⋅ ( − 3 ) + 81 +81 + 81
− 3 4 -3^4 − 3 4 3 3 3 − ( 3 ⋅ 3 ⋅ 3 ⋅ 3 ) -(3 \cdot 3 \cdot 3 \cdot 3) − ( 3 ⋅ 3 ⋅ 3 ⋅ 3 ) − 81 -81 − 81
( − 2 ) 3 (-2)^3 ( − 2 ) 3 − 2 -2 − 2 ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) (-2) \cdot (-2) \cdot (-2) ( − 2 ) ⋅ ( − 2 ) ⋅ ( − 2 ) − 8 -8 − 8
- − 2 3 -2^3 − 2 3 2 2 2 − ( 2 ⋅ 2 ⋅ 2 ) -(2 \cdot 2 \cdot 2) − ( 2 ⋅ 2 ⋅ 2 ) − 8 -8 − 8
- General Sign Rules for Negative Bases
For any real number a > 0 a > 0 a > 0 and integer n n n :
Even Power with Parentheses : ( − a ) n > 0 (-a)^n > 0 ( − a ) n > 0 because an even count of negative factors yields a positive product (e.g., ( − 4 ) 2 = + 16 (-4)^2 = +16 ( − 4 ) 2 = + 16 ).
Odd Power with Parentheses : ( − a ) n < 0 (-a)^n < 0 ( − a ) n < 0 because an odd count of negative factors retains the negative sign (e.g., ( − 4 ) 3 = − 64 (-4)^3 = -64 ( − 4 ) 3 = − 64 ).
Unparenthesized Negative Sign : − a n = − ( a n ) < 0 -a^n = -(a^n) < 0 − a n = − ( a n ) < 0 for all real a > 0 a > 0 a > 0 , because negation occurs after exponentiation in the standard Order of Operations (PEMDAS).
The Fundamental Laws of Exponents
When simplifying expressions involving integer exponents, seven universal algebraic laws govern all operations. These rules apply provided all bases are non-zero when division or negative powers are involved.
Summary Table: Core Laws of Exponents
Law Name Mathematical Rule Condition Conceptual Meaning
Product of Powers a m ⋅ a n = a m + n a^m \cdot a^n = a^{m+n} a m ⋅ a n = a m + n Same base a a a Add exponents when multiplying like bases
Quotient of Powers a m a n = a m − n \frac{a^m}{a^n} = a^{m-n} a n a m = a m − n a ≠ 0 a \neq 0 a = 0 , same base a a a Subtract denominator exponent from numerator exponent
Power of a Power ( a m ) n = a m ⋅ n (a^m)^n = a^{m \cdot n} ( a m ) n = a m ⋅ n Any real a a a Multiply exponents when raising a power to a power
Power of a Product ( a b ) n = a n ⋅ b n (ab)^n = a^n \cdot b^n ( ab ) n = a n ⋅ b n Any real a , b a, b a , b Distribute power to each factor in the product
Power of a Quotient ( a b ) n = a n b n \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ( b a ) n = b n a n b ≠ 0 b \neq 0 b = 0 Distribute power to numerator and denominator
Zero Exponent Rule a 0 = 1 a^0 = 1 a 0 = 1 a ≠ 0 a \neq 0 a = 0 Any non-zero base raised to power 0 0 0 equals 1 1 1
Negative Exponent Rule a − n = 1 a n a^{-n} = \frac{1}{a^n} a − n = a n 1 a ≠ 0 a \neq 0 a = 0 Negative power denotes reciprocal multiplicative inverse
1. Product of Powers Rule ( a m ⋅ a n = a m + n a^m \cdot a^n = a^{m+n} a m ⋅ a n = a m + n )
When multiplying exponential expressions sharing the exact same base , keep the base unchanged and add the exponents. Derivation: a 3 ⋅ a 2 = ( a ⋅ a ⋅ a ) ⋅ ( a ⋅ a ) = a ⋅ a ⋅ a ⋅ a ⋅ a = a 3 + 2 = a 5 \text{Derivation: } a^3 \cdot a^2 = (a \cdot a \cdot a) \cdot (a \cdot a) = a \cdot a \cdot a \cdot a \cdot a = a^{3+2} = a^5 Derivation: a 3 ⋅ a 2 = ( a ⋅ a ⋅ a ) ⋅ ( a ⋅ a ) = a ⋅ a ⋅ a ⋅ a ⋅ a = a 3 + 2 = a 5
Worked Examples :
x 4 ⋅ x 7 = x 4 + 7 = x 11 x^4 \cdot x^7 = x^{4+7} = x^{11} x 4 ⋅ x 7 = x 4 + 7 = x 11
2 3 ⋅ 2 5 = 2 3 + 5 = 2 8 = 256 2^3 \cdot 2^5 = 2^{3+5} = 2^8 = 256 2 3 ⋅ 2 5 = 2 3 + 5 = 2 8 = 256 (Note: Do NOT multiply the bases; 2 3 ⋅ 2 5 ≠ 4 8 2^3 \cdot 2^5 \neq 4^8 2 3 ⋅ 2 5 = 4 8 )
( y − 4 ) ⋅ ( y 9 ) = y − 4 + 9 = y 5 (y^{-4}) \cdot (y^9) = y^{-4 + 9} = y^5 ( y − 4 ) ⋅ ( y 9 ) = y − 4 + 9 = y 5
2. Quotient of Powers Rule ( a m a n = a m − n \frac{a^m}{a^n} = a^{m-n} a n a m = a m − n )
When dividing exponential expressions sharing the exact same non-zero base , keep the base unchanged and subtract the exponent of the denominator from the exponent of the numerator. Derivation: a 5 a 2 = a ⋅ a ⋅ a ⋅ a ⋅ a a ⋅ a = a ⋅ a ⋅ a = a 5 − 2 = a 3 \text{Derivation: } \frac{a^5}{a^2} = \frac{a \cdot a \cdot a \cdot \cancel{a} \cdot \cancel{a}}{\cancel{a} \cdot \cancel{a}} = a \cdot a \cdot a = a^{5-2} = a^3 Derivation: a 2 a 5 = a ⋅ a a ⋅ a ⋅ a ⋅ a ⋅ a = a ⋅ a ⋅ a = a 5 − 2 = a 3
Worked Examples :
- x 9 x 4 = x 9 − 4 = x 5 \frac{x^9}{x^4} = x^{9-4} = x^5 x 4 x 9 = x 9 − 4 = x 5
- 7 6 7 4 = 7 6 − 4 = 7 2 = 49 \frac{7^6}{7^4} = 7^{6-4} = 7^2 = 49 7 4 7 6 = 7 6 − 4 = 7 2 = 49
w 3 w − 2 = w 3 − ( − 2 ) = w 3 + 2 = w 5 \frac{w^3}{w^{-2}} = w^{3 - (-2)} = w^{3+2} = w^5 w − 2 w 3 = w 3 − ( − 2 ) = w 3 + 2 = w 5
3. Power of a Power Rule ( ( a m ) n = a m n (a^m)^n = a^{mn} ( a m ) n = a mn )
When raising an exponential expression to an additional power, keep the base and multiply the exponents together. Derivation: ( a 3 ) 2 = a 3 ⋅ a 3 = a 3 + 3 = a 3 ⋅ 2 = a 6 \text{Derivation: } (a^3)^2 = a^3 \cdot a^3 = a^{3+3} = a^{3 \cdot 2} = a^6 Derivation: ( a 3 ) 2 = a 3 ⋅ a 3 = a 3 + 3 = a 3 ⋅ 2 = a 6
Worked Examples :
- ( x 4 ) 5 = x 4 ⋅ 5 = x 20 (x^4)^5 = x^{4 \cdot 5} = x^{20} ( x 4 ) 5 = x 4 ⋅ 5 = x 20
- ( 2 2 ) 3 = 2 2 ⋅ 3 = 2 6 = 64 (2^2)^3 = 2^{2 \cdot 3} = 2^6 = 64 ( 2 2 ) 3 = 2 2 ⋅ 3 = 2 6 = 64
( z − 3 ) − 4 = z ( − 3 ) ⋅ ( − 4 ) = z 12 (z^{-3})^{-4} = z^{(-3) \cdot (-4)} = z^{12} ( z − 3 ) − 4 = z ( − 3 ) ⋅ ( − 4 ) = z 12
4. Power of a Product Rule ( ( a b ) n = a n b n (ab)^n = a^n b^n ( ab ) n = a n b n )
When a product of multiple factors is enclosed in parentheses and raised to an exponent, the exponent distributes to every factor inside the parentheses. Derivation: ( a b ) 3 = ( a b ) ⋅ ( a b ) ⋅ ( a b ) = ( a ⋅ a ⋅ a ) ⋅ ( b ⋅ b ⋅ b ) = a 3 b 3 \text{Derivation: } (ab)^3 = (ab) \cdot (ab) \cdot (ab) = (a \cdot a \cdot a) \cdot (b \cdot b \cdot b) = a^3 b^3 Derivation: ( ab ) 3 = ( ab ) ⋅ ( ab ) ⋅ ( ab ) = ( a ⋅ a ⋅ a ) ⋅ ( b ⋅ b ⋅ b ) = a 3 b 3
Worked Examples :
( 2 x ) 4 = 2 4 ⋅ x 4 = 16 x 4 (2x)^4 = 2^4 \cdot x^4 = 16x^4 ( 2 x ) 4 = 2 4 ⋅ x 4 = 16 x 4 (Note: The numeric coefficient 2 is also raised to the 4th power)
( − 3 x 2 y 3 ) 3 = ( − 3 ) 3 ⋅ ( x 2 ) 3 ⋅ ( y 3 ) 3 = − 27 x 6 y 9 (-3x^2 y^3)^3 = (-3)^3 \cdot (x^2)^3 \cdot (y^3)^3 = -27 x^6 y^9 ( − 3 x 2 y 3 ) 3 = ( − 3 ) 3 ⋅ ( x 2 ) 3 ⋅ ( y 3 ) 3 = − 27 x 6 y 9
( 4 a − 2 b 3 ) 2 = 4 2 ⋅ ( a − 2 ) 2 ⋅ ( b 3 ) 2 = 16 a − 4 b 6 = 16 b 6 a 4 (4a^{-2} b^3)^2 = 4^2 \cdot (a^{-2})^2 \cdot (b^3)^2 = 16 a^{-4} b^6 = \frac{16b^6}{a^4} ( 4 a − 2 b 3 ) 2 = 4 2 ⋅ ( a − 2 ) 2 ⋅ ( b 3 ) 2 = 16 a − 4 b 6 = a 4 16 b 6
5. Power of a Quotient Rule ( ( a b ) n = a n b n \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} ( b a ) n = b n a n )
When a fraction is raised to an exponent, the exponent applies independently to both the numerator and the denominator. Derivation: ( a b ) 3 = a b ⋅ a b ⋅ a b = a ⋅ a ⋅ a b ⋅ b ⋅ b = a 3 b 3 \text{Derivation: } \left(\frac{a}{b}\right)^3 = \frac{a}{b} \cdot \frac{a}{b} \cdot \frac{a}{b} = \frac{a \cdot a \cdot a}{b \cdot b \cdot b} = \frac{a^3}{b^3} Derivation: ( b a ) 3 = b a ⋅ b a ⋅ b a = b ⋅ b ⋅ b a ⋅ a ⋅ a = b 3 a 3
Worked Examples :
( x 5 ) 3 = x 3 5 3 = x 3 125 \left(\frac{x}{5}\right)^3 = \frac{x^3}{5^3} = \frac{x^3}{125} ( 5 x ) 3 = 5 3 x 3 = 125 x 3
( 2 x 3 y 4 ) 4 = 2 4 ( x 3 ) 4 ( y 4 ) 4 = 16 x 12 y 16 \left(\frac{2x^3}{y^4}\right)^4 = \frac{2^4 (x^3)^4}{(y^4)^4} = \frac{16x^{12}}{y^{16}} ( y 4 2 x 3 ) 4 = ( y 4 ) 4 2 4 ( x 3 ) 4 = y 16 16 x 12
- Zero and Negative Exponents
- The Zero Exponent Rule ( a 0 = 1 a^0 = 1 a 0 = 1 )
The zero exponent rule is a direct mathematical consequence of the Quotient of Powers rule. Consider dividing any non-zero term a n a^n a n by itself:
By standard arithmetic division: a n a n = 1 \frac{a^n}{a^n} = 1 a n a n = 1 (any non-zero quantity divided by itself equals 1 1 1 ).
By the Quotient of Powers rule: a n a n = a n − n = a 0 \frac{a^n}{a^n} = a^{n-n} = a^0 a n a n = a n − n = a 0 .
Setting the two equivalent results equal yields: a 0 = 1 ( for all a ≠ 0 ) a^0 = 1 \quad (\text{for all } a \neq 0) a 0 = 1 ( for all a = 0 )
Important Notes :
- 8 0 = 1 8^0 = 1 8 0 = 1
- ( − 145 ) 0 = 1 (-145)^0 = 1 ( − 145 ) 0 = 1
- − 145 0 = − ( 145 0 ) = − 1 -145^0 = -(145^0) = -1 − 14 5 0 = − ( 14 5 0 ) = − 1
( 5 x 2 y 7 ) 0 = 1 (5x^2 y^7)^0 = 1 ( 5 x 2 y 7 ) 0 = 1 (provided x ≠ 0 , y ≠ 0 x \neq 0, y \neq 0 x = 0 , y = 0 )
5 x 0 = 5 ⋅ ( x 0 ) = 5 ⋅ 1 = 5 5x^0 = 5 \cdot (x^0) = 5 \cdot 1 = 5 5 x 0 = 5 ⋅ ( x 0 ) = 5 ⋅ 1 = 5 (the exponent 0 0 0 applies only to x x x )
Indeterminate Form : 0 0 0^0 0 0 is mathematically undefined.
The Negative Exponent Rule ( a − n = 1 a n a^{-n} = \frac{1}{a^n} a − n = a n 1 )
A negative exponent indicates the reciprocal multiplicative inverse of the base raised to the positive power. It does NOT make the number itself negative. Derivation: a − n = a 0 − n = a 0 a n = 1 a n \text{Derivation: } a^{-n} = a^{0 - n} = \frac{a^0}{a^n} = \frac{1}{a^n} Derivation: a − n = a 0 − n = a n a 0 = a n 1
Similarly, a negative exponent in the denominator moves the factor to the numerator: 1 a − n = 1 1 a n = 1 ⋅ a n 1 = a n \frac{1}{a^{-n}} = \frac{1}{\frac{1}{a^n}} = 1 \cdot \frac{a^n}{1} = a^n a − n 1 = a n 1 1 = 1 ⋅ 1 a n = a n
The Reciprocal Fraction Rule for Negative Powers
When an entire fraction is raised to a negative power, inverting the fraction changes the sign of the exponent: ( a b ) − n = ( b a ) n = b n a n ( a ≠ 0 , b ≠ 0 ) \left(\frac{a}{b}\right)^{-n} = \left(\frac{b}{a}\right)^n = \frac{b^n}{a^n} \quad (a \neq 0, b \neq 0) ( b a ) − n = ( a b ) n = a n b n ( a = 0 , b = 0 )
Worked Examples :
- 4 − 2 = 1 4 2 = 1 16 4^{-2} = \frac{1}{4^2} = \frac{1}{16} 4 − 2 = 4 2 1 = 16 1
- 2 − 5 = 1 2 5 = 1 32 2^{-5} = \frac{1}{2^5} = \frac{1}{32} 2 − 5 = 2 5 1 = 32 1
- 1 3 − 3 = 3 3 = 27 \frac{1}{3^{-3}} = 3^3 = 27 3 − 3 1 = 3 3 = 27
( 2 5 ) − 3 = ( 5 2 ) 3 = 5 3 2 3 = 125 8 \left(\frac{2}{5}\right)^{-3} = \left(\frac{5}{2}\right)^3 = \frac{5^3}{2^3} = \frac{125}{8} ( 5 2 ) − 3 = ( 2 5 ) 3 = 2 3 5 3 = 8 125
x − 4 y 3 z − 2 = y 3 z 2 x 4 \frac{x^{-4} y^3}{z^{-2}} = \frac{y^3 z^2}{x^4} z − 2 x − 4 y 3 = x 4 y 3 z 2
Systematic Algorithm for Simplifying Complex Rational Expressions
To simplify complicated algebraic expressions with integer exponents on the ACCUPLACER test, follow this structured 5-step algorithm: Step 1: Expand Outer Powers
Apply (ab)^n = a^n b^n and (a^m)^n = a^(mn) to eliminate outer parentheses.
Step 2: Group and Simplify Numerical Coefficients
Isolate all constant numbers, multiply them in numerator and denominator, and reduce fractions.
Step 3: Combine Like Bases Within the Same Level
Use Product Rule (a^m · a^n = a^(m+n)) to merge identical variable bases in numerator and denominator.
Step 4: Cancel Bases Across the Fraction Bar
Use Quotient Rule (a^m / a^n = a^(m-n)) to reduce variables between numerator and denominator.
Step 5: Convert All Negative Exponents to Positive Exponents
Move any base with a negative exponent across the fraction bar (a^(-k) = 1/a^k).
- Comprehensive Worked Examples
- Worked Example 1: Multi-Variable Simplification with Coefficients
Simplify the following expression and write the final answer using only positive exponents: ( 3 x 3 y − 2 ) 2 ⋅ ( 2 x − 1 y 4 ) 6 x 4 y − 3 \frac{(3x^3 y^{-2})^2 \cdot (2x^{-1} y^4)}{6x^4 y^{-3}} 6 x 4 y − 3 ( 3 x 3 y − 2 ) 2 ⋅ ( 2 x − 1 y 4 )
Solution Plan & Step-by-Step Execution :
Expand the outer power in the first factor : ( 3 x 3 y − 2 ) 2 = 3 2 ⋅ ( x 3 ) 2 ⋅ ( y − 2 ) 2 = 9 x 6 y − 4 (3x^3 y^{-2})^2 = 3^2 \cdot (x^3)^2 \cdot (y^{-2})^2 = 9 x^6 y^{-4} ( 3 x 3 y − 2 ) 2 = 3 2 ⋅ ( x 3 ) 2 ⋅ ( y − 2 ) 2 = 9 x 6 y − 4
Multiply the factors in the numerator : Numerator = ( 9 x 6 y − 4 ) ⋅ ( 2 x − 1 y 4 ) = ( 9 ⋅ 2 ) ⋅ ( x 6 + ( − 1 ) ) ⋅ ( y − 4 + 4 ) = 18 x 5 y 0 = 18 x 5 \text{Numerator} = (9 x^6 y^{-4}) \cdot (2 x^{-1} y^4) = (9 \cdot 2) \cdot (x^{6 + (-1)}) \cdot (y^{-4 + 4}) = 18 x^5 y^0 = 18 x^5 Numerator = ( 9 x 6 y − 4 ) ⋅ ( 2 x − 1 y 4 ) = ( 9 ⋅ 2 ) ⋅ ( x 6 + ( − 1 ) ) ⋅ ( y − 4 + 4 ) = 18 x 5 y 0 = 18 x 5
(Since y 0 = 1 y^0 = 1 y 0 = 1 )
Set up the combined fraction : 18 x 5 6 x 4 y − 3 \frac{18 x^5}{6 x^4 y^{-3}} 6 x 4 y − 3 18 x 5
Divide numerical coefficients and apply Quotient Rule to variables : 18 6 = 3 \frac{18}{6} = 3 6 18 = 3 x 5 − 4 = x 1 = x x^{5 - 4} = x^1 = x x 5 − 4 = x 1 = x 1 y − 3 = y 3 \frac{1}{y^{-3}} = y^3 y − 3 1 = y 3
- Combine into final form : 3 x y 3 3 x y^3 3 x y 3
- Worked Example 2: Negative Fraction Powers and Variable Rational Fractions
Simplify the expression completely: ( 4 a − 3 b 2 2 a 2 b − 4 ) − 2 \left(\frac{4a^{-3} b^2}{2a^2 b^{-4}}\right)^{-2} ( 2 a 2 b − 4 4 a − 3 b 2 ) − 2
Solution Plan & Step-by-Step Execution :
Simplify the inside of the parentheses first :
Numerical coefficients: 4 2 = 2 \frac{4}{2} = 2 2 4 = 2
Base a a a : a − 3 a 2 = a − 3 − 2 = a − 5 \frac{a^{-3}}{a^2} = a^{-3 - 2} = a^{-5} a 2 a − 3 = a − 3 − 2 = a − 5
Base b b b : b 2 b − 4 = b 2 − ( − 4 ) = b 2 + 4 = b 6 \frac{b^2}{b^{-4}} = b^{2 - (-4)} = b^{2 + 4} = b^6 b − 4 b 2 = b 2 − ( − 4 ) = b 2 + 4 = b 6 Inside Expression = 2 a − 5 b 6 \text{Inside Expression} = 2 a^{-5} b^6 Inside Expression = 2 a − 5 b 6
Apply the outer exponent − 2 -2 − 2 to each factor : ( 2 a − 5 b 6 ) − 2 = 2 − 2 ⋅ ( a − 5 ) − 2 ⋅ ( b 6 ) − 2 (2 a^{-5} b^6)^{-2} = 2^{-2} \cdot (a^{-5})^{-2} \cdot (b^6)^{-2} ( 2 a − 5 b 6 ) − 2 = 2 − 2 ⋅ ( a − 5 ) − 2 ⋅ ( b 6 ) − 2
Multiply exponents and evaluate coefficients : 2 − 2 = 1 2 2 = 1 4 2^{-2} = \frac{1}{2^2} = \frac{1}{4} 2 − 2 = 2 2 1 = 4 1 ( a − 5 ) − 2 = a ( − 5 ) ⋅ ( − 2 ) = a 10 (a^{-5})^{-2} = a^{(-5) \cdot (-2)} = a^{10} ( a − 5 ) − 2 = a ( − 5 ) ⋅ ( − 2 ) = a 10 ( b 6 ) − 2 = b 6 ⋅ ( − 2 ) = b − 12 = 1 b 12 (b^6)^{-2} = b^{6 \cdot (-2)} = b^{-12} = \frac{1}{b^{12}} ( b 6 ) − 2 = b 6 ⋅ ( − 2 ) = b − 12 = b 12 1
- Combine into a single rational expression : a 10 4 b 12 \frac{a^{10}}{4b^{12}} 4 b 12 a 10
- Worked Example 3: Order of Operations with Signs, Zero, and Negative Powers
Evaluate the exact arithmetic value of the expression: − 4 0 + ( − 4 ) 0 − 3 − 2 + ( 1 2 ) − 3 -4^0 + (-4)^0 - 3^{-2} + \left(\frac{1}{2}\right)^{-3} − 4 0 + ( − 4 ) 0 − 3 − 2 + ( 2 1 ) − 3
Step-by-Step Solution :
Evaluate − 4 0 -4^0 − 4 0 : By order of operations, exponent precedes negation ⟹ − ( 4 0 ) = − 1 \implies -(4^0) = -1 ⟹ − ( 4 0 ) = − 1 .
Evaluate ( − 4 ) 0 (-4)^0 ( − 4 ) 0 : The base is − 4 -4 − 4 , raised to power 0 0 0 ⟹ + 1 \implies +1 ⟹ + 1 .
Evaluate 3 − 2 3^{-2} 3 − 2 : Negative power gives reciprocal ⟹ 1 3 2 = 1 9 \implies \frac{1}{3^2} = \frac{1}{9} ⟹ 3 2 1 = 9 1 .
Evaluate ( 1 2 ) − 3 \left(\frac{1}{2}\right)^{-3} ( 2 1 ) − 3 : Invert fraction and apply positive power ⟹ 2 3 = 8 \implies 2^3 = 8 ⟹ 2 3 = 8 .
Sum the evaluated components : Total = − 1 + 1 − 1 9 + 8 = 0 − 1 9 + 8 = 8 − 1 9 = 72 9 − 1 9 = 71 9 \text{Total} = -1 + 1 - \frac{1}{9} + 8 = 0 - \frac{1}{9} + 8 = 8 - \frac{1}{9} = \frac{72}{9} - \frac{1}{9} = \frac{71}{9} Total = − 1 + 1 − 9 1 + 8 = 0 − 9 1 + 8 = 8 − 9 1 = 9 72 − 9 1 = 9 71
Common Pitfalls & ACCUPLACER Exam Traps
Distributing Exponents Across Addition / Subtraction : Exponentiation does NOT distribute over sums: ( x + y ) 2 = x 2 + 2 x y + y 2 ≠ x 2 + y 2 (x + y)^2 = x^2 + 2xy + y^2 \neq x^2 + y^2 ( x + y ) 2 = x 2 + 2 x y + y 2 = x 2 + y 2 . Similarly, ( x − y ) − 1 ≠ 1 x − 1 y (x - y)^{-1} \neq \frac{1}{x} - \frac{1}{y} ( x − y ) − 1 = x 1 − y 1 .
Multiplying Common Bases : When multiplying 3 4 ⋅ 3 5 3^4 \cdot 3^5 3 4 ⋅ 3 5 , students often write 9 9 9^9 9 9 . The base stays the same: 3 4 + 5 = 3 9 3^{4+5} = 3^9 3 4 + 5 = 3 9 .
Confusing Negative Exponents with Negative Values : 2 − 4 = 1 16 > 0 2^{-4} = \frac{1}{16} > 0 2 − 4 = 16 1 > 0 . A negative exponent never makes a positive base negative.
Coefficient Exponent Neglect : In ( 3 x ) 3 (3x)^3 ( 3 x ) 3 , the 3 is also cubed: ( 3 x ) 3 = 27 x 3 (3x)^3 = 27x^3 ( 3 x ) 3 = 27 x 3 , not 3 x 3 3x^3 3 x 3 .
Sign Errors with Denominator Exponent Subtraction : In x 4 x − 6 \frac{x^4}{x^{-6}} x − 6 x 4 , subtracting gives 4 − ( − 6 ) = 4 + 6 = 10 ⟹ x 10 4 - (-6) = 4 + 6 = 10 \implies x^{10} 4 − ( − 6 ) = 4 + 6 = 10 ⟹ x 10 , not x − 2 x^{-2} x − 2 or x 2 x^2 x 2 .