Study guide
4.2 Functions & Function Notation
ALEKS Math Placement Study Guide Exam
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1 Chapter 1: ALEKS PPL Overview & Strategy
1.1 What ALEKS PPL Is 1.2 How Placement Works 1.3 The Prep & Learning Module & Retake Strategy
2 Chapter 2: Arithmetic & Number Sense
2.1 Real Numbers & Operations 2.2 Fractions, Decimals & Percents 2.3 Ratios, Proportions & Unit Conversion
3 Chapter 3: Algebra Essentials
3.1 Linear Equations & Inequalities 3.2 Exponents & Polynomials 3.3 Factoring & Rational Expressions 3.4 Quadratic Equations
4 Chapter 4: Functions, Graphs & Geometry
4.1 Lines, Slope & Graphing 4.2 Functions & Function Notation 4.3 Geometry & Measurement 4.4 Coordinate Geometry
5 Chapter 5: Advanced Readiness — Precalculus & Trig
5.1 Exponential & Logarithmic Expressions 5.2 Radicals, Rational Exponents & Complex Numbers 5.3 Trigonometry Basics 5.4 Sequences, Functions Review & Exam Readiness
4.2 Functions & Function Notation
Key Takeaways Explain This Topic AI
A function assigns exactly one output to each input; no input may map to two outputs.
The vertical line test confirms a graph is a function: no vertical line touches it more than once.
Domain is the set of allowed inputs (x); range is the set of resulting outputs (y).
f(x) is read 'f of x'; evaluating means substituting a value for x and simplifying.
A composite (f∘g)(x) = f(g(x)) means apply g first, then feed the result into f.
Last updated: June 2026
What Is a Function?
A function is a rule that assigns to each input exactly one output. Think of it as a machine: put in a number x, get out a single number y. The key restriction is the word exactly one — an input is never allowed to produce two different outputs.
Functions can be given as equations (y = 2x + 1), tables, graphs, or sets of ordered pairs. The set {(1, 3), (2, 5), (3, 7)} is a function because each first coordinate appears once. But {(1, 3), (1, 4)} is not a function, because the input 1 maps to both 3 and 4.
The vertical line test. A graph represents a function if and only if no vertical line crosses it more than once . If any vertical line hits the graph twice, that x-value has two y-values, violating the definition. A straight line (non-vertical) passes the test; a parabola y = x² passes; but a sideways parabola x = y² or a full circle fails — a vertical line through it hits two points.
Worked example. Is the circle x² + y² = 25 a function? Solving for y gives y = ±√(25 − x²). The ± means most x-values (like x = 0 → y = ±5) produce two outputs, so a vertical line cuts it twice. It is not a function.
Domain, Range & Function Notation
The domain is the set of all allowed input (x) values; the range is the set of all resulting output (y) values. On a placement test, the two domain restrictions to watch for are:
Division by zero — exclude any x that makes a denominator 0.
Even roots of negatives — the inside of a square root must be ≥ 0.
Worked example (domain). Find the domain of f(x) = 1/(x − 4). The denominator is 0 when x = 4, so the domain is all real numbers except x = 4 .
Worked example (domain with a root). Find the domain of g(x) = √(x − 3). The radicand must satisfy x − 3 ≥ 0, so x ≥ 3. The domain is [3, ∞).
Function notation writes the output as f(x) , read "f of x." It does not mean f times x — it names the output of function f at input x. To evaluate , substitute the value everywhere x appears.
Worked example. If f(x) = 3x² − 2x + 1, find f(−2):
f(−2) = 3(−2)² − 2(−2) + 1 = 3(4) + 4 + 1 = 12 + 4 + 1 = 17 .
Notice (−2)² = 4 (square first), and −2(−2) = +4. These sign steps are where errors creep in.
Composite Functions & Transformations
A composite function chains two functions: (f∘g)(x) = f(g(x)) means "do g first, then apply f to that result." Work from the inside out.
Worked example. Let f(x) = x + 5 and g(x) = x². Find (f∘g)(3) and (g∘f)(3).
(f∘g)(3) = f(g(3)) = f(9) = 9 + 5 = 14 .
(g∘f)(3) = g(f(3)) = g(8) = 8² = 64 .
Order matters — composition is not commutative.
Basic transformations shift or reflect a graph y = f(x):
- Transformation Effect on the graph
- f(x) + k shifts up k units
- f(x) − k shifts down k units
- f(x + h) shifts left h units
- f(x − h) shifts right h units
- −f(x) reflects over the x-axis
- f(−x) reflects over the y-axis
Worked example. Starting from y = x², the graph y = (x − 3)² + 2 is the parabola shifted 3 right and 2 up , so its vertex moves from (0, 0) to (3, 2).
Common mistake: Horizontal shifts feel backwards — f(x + 4) moves the graph left 4, not right. The shift is opposite the sign inside the parentheses. Also, do not read f(x) as multiplication: f(x) = x² means "square the input," so f(3) = 9, never 3x.
Reading Functions from Graphs & Tables
A placement test often shows a graph and asks you to read off values. To find f(a) , locate x = a on the horizontal axis, move up or down to the curve, then read the y-value. To solve f(x) = b , do the reverse: find where the height equals b and read the x-value(s).
Worked example. Suppose a graph passes through (0, 4), (2, 0), and (4, −4). Then f(0) = 4, f(2) = 0, and f(4) = −4. The point where f(x) = 0 — here x = 2 — is called a zero or root of the function, the x-intercept of its graph.
Range from a graph. The range is the set of all y-values the graph actually reaches. A parabola y = x² opening upward from vertex (0, 0) has range y ≥ 0, because outputs are never negative — squaring can't produce a negative number.
Worked example (evaluate a piecewise idea). If f(x) = |x| (absolute value), then f(−5) = 5 and f(5) = 5; the V-shaped graph has its lowest point at the origin and range y ≥ 0.
Even vs. odd quick check. A graph symmetric about the y-axis satisfies f(−x) = f(x) (even, like x²); one symmetric about the origin satisfies f(−x) = −f(x) (odd, like x³). You won't need formal proofs on a placement test, but recognizing this symmetry helps you sketch and check answers quickly. Always confirm a candidate output by re-substituting it into the rule.