Mathematics Domain (AR + MK)

Geometry

Geometry

Key Takeaways

  • Memorize key formulas: Area of triangle = 1/2 base times height; Area of circle = pi times r^2.

  • The sum of angles in a triangle is always 180 degrees; in a quadrilateral, 360 degrees.

  • The Pythagorean theorem (a^2 + b^2 = c^2) applies only to right triangles.

  • Know the special right triangles: 30-60-90 (1, sqrt(3), 2) and 45-45-90 (1, 1, sqrt(2)).

  • For volume problems, multiply the base area by height for prisms and cylinders.

Last updated: January 2026

MK Subtest: Geometry questions make up about 30-35% of the Mathematics Knowledge section. Memorize the key formulas!

Angles

Types of Angles

TypeDegreesExample
AcuteLess than 90°45°
RightExactly 90°90°
ObtuseBetween 90° and 180°120°
StraightExactly 180°180°

Angle Relationships

RelationshipProperty
ComplementaryTwo angles that sum to 90°
SupplementaryTwo angles that sum to 180°
VerticalOpposite angles formed by intersecting lines (equal)

Worked Example: Complementary Angles

Problem: Two angles are complementary. One angle is 35°. What is the other?

Solution: 90°−35°=55°90° - 35° = 55°

Triangles

Triangle Angle Sum

The sum of all angles in a triangle is always 180°.

Types of Triangles

By SidesDescriptionBy AnglesDescription
EquilateralAll sides equalAcuteAll angles < 90°
IsoscelesTwo sides equalRightOne angle = 90°
ScaleneNo sides equalObtuseOne angle > 90°

The Pythagorean Theorem

For right triangles only:

a2+b2=c2a^2 + b^2 = c^2

where cc is the hypotenuse (longest side, opposite the right angle)

Common Pythagorean Triples (Memorize These!)

TripleMultiple Examples
3, 4, 56-8-10, 9-12-15, 12-16-20
5, 12, 1310-24-26
8, 15, 17
7, 24, 25

Worked Example: Pythagorean Theorem

Problem: A right triangle has legs of 6 and 8. Find the hypotenuse.

Solution: Recognize 6-8-? is a multiple of 3-4-5 (multiplied by 2):

  • If 3-4-5, then 6-8-10

Or calculate: c2=62+82=36+64=100c^2 = 6^2 + 8^2 = 36 + 64 = 100, so c=10c = 10

Special Right Triangles

45-45-90 Triangle (Isosceles Right):

  • Sides in ratio: 1:1:21 : 1 : \sqrt{2}
  • If legs = 5, hypotenuse = 525\sqrt{2}

30-60-90 Triangle:

  • Sides in ratio: 1:3:21 : \sqrt{3} : 2
  • Opposite 30°: shortest side (1)
  • Opposite 60°: middle side (3\sqrt{3})
  • Opposite 90°: longest side (2)

Triangle Area

Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}

Worked Example: Triangle Area

Problem: Find the area of a triangle with base 12 and height 8.

Solution: Area=12×12×8=48\text{Area} = \frac{1}{2} \times 12 \times 8 = 48 square units

Quadrilaterals

Quadrilateral Properties

ShapePropertiesArea Formula
Square4 equal sides, 4 right angless2s^2
RectangleOpposite sides equal, 4 right anglesl×wl \times w
ParallelogramOpposite sides parallel and equalb×hb \times h
TrapezoidOne pair of parallel sides12(b1+b2)×h\frac{1}{2}(b_1 + b_2) \times h

Worked Example: Trapezoid Area

Problem: A trapezoid has parallel sides of 8 and 12, with height 5. Find the area.

Solution: Area=12(8+12)×5=12(20)×5=50\text{Area} = \frac{1}{2}(8 + 12) \times 5 = \frac{1}{2}(20) \times 5 = 50 square units

Circles

Circle Formulas

MeasurementFormula
CircumferenceC=2πr=πdC = 2\pi r = \pi d
AreaA=πr2A = \pi r^2

Approximation: Use π≈3.14\pi \approx 3.14 or 227\frac{22}{7} for calculations

Key Terms

  • Radius (r): Distance from center to edge
  • Diameter (d): Distance across through center (d=2rd = 2r)
  • Chord: Line segment connecting two points on the circle
  • Arc: Portion of the circumference

Worked Example: Circle Calculations

Problem: A circle has radius 7. Find its circumference and area.

Solution:

  • Circumference: C=2π(7)=14π≈44C = 2\pi(7) = 14\pi \approx 44 units
  • Area: A=π(7)2=49π≈154A = \pi(7)^2 = 49\pi \approx 154 square units

Volume and Surface Area

3D Shape Formulas

ShapeVolumeSurface Area
Cubes3s^36s26s^2
Rectangular Prisml×w×hl \times w \times h2(lw+lh+wh)2(lw + lh + wh)
Cylinderπr2h\pi r^2 h2πr2+2πrh2\pi r^2 + 2\pi rh
Sphere43πr3\frac{4}{3}\pi r^34πr24\pi r^2
Cone13πr2h\frac{1}{3}\pi r^2 hπr2+πrs\pi r^2 + \pi r s

Worked Example: Cylinder Volume

Problem: Find the volume of a cylinder with radius 3 and height 10.

Solution: V=πr2h=π(3)2(10)=90π≈283V = \pi r^2 h = \pi (3)^2 (10) = 90\pi \approx 283 cubic units

Test Your Knowledge

A right triangle has legs of 5 and 12. What is the length of the hypotenuse?

  1. 13

  2. 15

  3. 17

  4. 169

Test Your Knowledge

What is the area of a circle with radius 5? (Use pi = 3.14)

  1. 15.7 sq units

  2. 31.4 sq units

  3. 78.5 sq units

  4. 157 sq units

Test Your Knowledge

Two angles are supplementary. If one angle measures 115 degrees, what is the measure of the other angle?

  1. 25 degrees

  2. 65 degrees

  3. 75 degrees

  4. 115 degrees

Test Your Knowledge

A rectangular box has dimensions 4 x 5 x 6. What is its volume?

  1. 15 cubic units

  2. 60 cubic units

  3. 120 cubic units

  4. 148 cubic units