Registered Public Utility Engineer — HVAC (China)

Practice session

According to moist air thermodynamics and GB 50736-2012, moist air enthalpy $h$ (in $\text{kJ/kg dry air}$) at atmospheric pressure is calculated as $h = 1.005 t + d(2501 + 1.86 t)$, where $t$ is dry-bulb temperature ($^\circ\text{C}$) and $d$ is moisture content (humidity ratio in $\text{kg/kg dry air}$). What is the specific enthalpy of moist air at $t = 25^\circ\text{C}$ with a moisture content of $d = 0.010\text{ kg/kg}$ ($10\text{ g/kg}$)?

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